Base | Representation |
---|---|
bin | 11110110010101111100000… |
… | …000100111100001011000111 |
3 | 122202111211022011212202200121 |
4 | 132302233200010330023013 |
5 | 120222324302014422412 |
6 | 1200010534042522411 |
7 | 40345243223461213 |
oct | 3662574004741307 |
9 | 582454264782617 |
10 | 135428373201607 |
11 | 3a17393a075432 |
12 | 13232b14206407 |
13 | 5a74ac12c3175 |
14 | 2562aa8083943 |
15 | 109cc09598107 |
hex | 7b2be013c2c7 |
135428373201607 has 2 divisors, whose sum is σ = 135428373201608. Its totient is φ = 135428373201606.
The previous prime is 135428373201551. The next prime is 135428373201613. The reversal of 135428373201607 is 706102373824531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135428373201607 - 235 = 135394013463239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135428373201307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67714186600803 + 67714186600804.
It is an arithmetic number, because the mean of its divisors is an integer number (67714186600804).
Almost surely, 2135428373201607 is an apocalyptic number.
135428373201607 is a deficient number, since it is larger than the sum of its proper divisors (1).
135428373201607 is an equidigital number, since it uses as much as digits as its factorization.
135428373201607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5080320, while the sum is 52.
The spelling of 135428373201607 in words is "one hundred thirty-five trillion, four hundred twenty-eight billion, three hundred seventy-three million, two hundred one thousand, six hundred seven".
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