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135428373267133 is a prime number
BaseRepresentation
bin11110110010101111100000…
…000101001100001010111101
3122202111211022012000002120111
4132302233200011030022331
5120222324302024022013
61200010534044150021
740345243224153232
oct3662574005141275
9582454265002514
10135428373267133
113a17393a10a691
1213232b14238311
135a74ac1316c3b
142562aa809d789
15109cc095ac73d
hex7b2be014c2bd

135428373267133 has 2 divisors, whose sum is σ = 135428373267134. Its totient is φ = 135428373267132.

The previous prime is 135428373267101. The next prime is 135428373267181. The reversal of 135428373267133 is 331762373824531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91383409324089 + 44044963943044 = 9559467^2 + 6636638^2 .

It is a cyclic number.

It is not a de Polignac number, because 135428373267133 - 25 = 135428373267101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135428373217133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67714186633566 + 67714186633567.

It is an arithmetic number, because the mean of its divisors is an integer number (67714186633567).

Almost surely, 2135428373267133 is an apocalyptic number.

It is an amenable number.

135428373267133 is a deficient number, since it is larger than the sum of its proper divisors (1).

135428373267133 is an equidigital number, since it uses as much as digits as its factorization.

135428373267133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 45722880, while the sum is 58.

The spelling of 135428373267133 in words is "one hundred thirty-five trillion, four hundred twenty-eight billion, three hundred seventy-three million, two hundred sixty-seven thousand, one hundred thirty-three".