Base | Representation |
---|---|
bin | 10011101101010011111… |
… | …101011100010111010011 |
3 | 11210110202010020201220121 |
4 | 103231103331130113103 |
5 | 134142123232023011 |
6 | 2514100104451111 |
7 | 166563252141454 |
oct | 23552375342723 |
9 | 4713663221817 |
10 | 1354323314131 |
11 | 482402227127 |
12 | 19a588179a97 |
13 | 9a93475a3b8 |
14 | 4979a15112b |
15 | 25368106e71 |
hex | 13b53f5c5d3 |
1354323314131 has 2 divisors, whose sum is σ = 1354323314132. Its totient is φ = 1354323314130.
The previous prime is 1354323314059. The next prime is 1354323314143. The reversal of 1354323314131 is 1314133234531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1354323314131 - 225 = 1354289759699 is a prime.
It is a super-2 number, since 2×13543233141312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1354323314731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677161657065 + 677161657066.
It is an arithmetic number, because the mean of its divisors is an integer number (677161657066).
Almost surely, 21354323314131 is an apocalyptic number.
1354323314131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354323314131 is an equidigital number, since it uses as much as digits as its factorization.
1354323314131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 38880, while the sum is 34.
Adding to 1354323314131 its reverse (1314133234531), we get a palindrome (2668456548662).
The spelling of 1354323314131 in words is "one trillion, three hundred fifty-four billion, three hundred twenty-three million, three hundred fourteen thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •