Base | Representation |
---|---|
bin | 10011101101010011111… |
… | …101011100010111010010 |
3 | 11210110202010020201220120 |
4 | 103231103331130113102 |
5 | 134142123232023010 |
6 | 2514100104451110 |
7 | 166563252141453 |
oct | 23552375342722 |
9 | 4713663221816 |
10 | 1354323314130 |
11 | 482402227126 |
12 | 19a588179a96 |
13 | 9a93475a3b7 |
14 | 4979a15112a |
15 | 25368106e70 |
hex | 13b53f5c5d2 |
1354323314130 has 16 divisors (see below), whose sum is σ = 3250375953984. Its totient is φ = 361152883760.
The previous prime is 1354323314059. The next prime is 1354323314131. The reversal of 1354323314130 is 314133234531.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 1354323314091 and 1354323314100.
It is not an unprimeable number, because it can be changed into a prime (1354323314131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22572055206 + ... + 22572055265.
It is an arithmetic number, because the mean of its divisors is an integer number (203148497124).
Almost surely, 21354323314130 is an apocalyptic number.
1354323314130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1354323314130 is an abundant number, since it is smaller than the sum of its proper divisors (1896052639854).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1354323314130 is a wasteful number, since it uses less digits than its factorization.
1354323314130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45144110481.
The product of its (nonzero) digits is 38880, while the sum is 33.
Adding to 1354323314130 its reverse (314133234531), we get a palindrome (1668456548661).
The spelling of 1354323314130 in words is "one trillion, three hundred fifty-four billion, three hundred twenty-three million, three hundred fourteen thousand, one hundred thirty".
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