13543314541 has 4 divisors (see below), whose sum is σ = 13745453632. Its totient is φ = 13341175452.

The previous prime is 13543314527. The next prime is 13543314557. The reversal of 13543314541 is 14541334531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13543314541 - 2⁵ = 13543314509 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13543314497 and 13543314506.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13543314511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101069445 + ... + 101069578.

It is an arithmetic number, because the mean of its divisors is an integer number (3436363408).

Almost surely, 2^13543314541 is an apocalyptic number.

It is an amenable number.

13543314541 is a deficient number, since it is larger than the sum of its proper divisors (202139091).

13543314541 is an equidigital number, since it uses as much as digits as its factorization.

13543314541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 202139090.

The product of its digits is 43200, while the sum is 34.

The spelling of 13543314541 in words is "thirteen billion, five hundred forty-three million, three hundred fourteen thousand, five hundred forty-one".