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1354354250351 is a prime number
BaseRepresentation
bin10011101101010101110…
…011011101001001101111
311210110211021110110102112
4103231111303131021233
5134142204142002401
62514103131514235
7166564106116514
oct23552563351157
94713737413375
101354354250351
11482418736a53
1219a5965b897b
139a93ac9c55b
14497a02c530b
152536abb83bb
hex13b55cdd26f

1354354250351 has 2 divisors, whose sum is σ = 1354354250352. Its totient is φ = 1354354250350.

The previous prime is 1354354250297. The next prime is 1354354250461. The reversal of 1354354250351 is 1530524534531.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1354354250351 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1354354250299 and 1354354250308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1354354250251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677177125175 + 677177125176.

It is an arithmetic number, because the mean of its divisors is an integer number (677177125176).

Almost surely, 21354354250351 is an apocalyptic number.

1354354250351 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354354250351 is an equidigital number, since it uses as much as digits as its factorization.

1354354250351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540000, while the sum is 41.

Adding to 1354354250351 its reverse (1530524534531), we get a palindrome (2884878784882).

The spelling of 1354354250351 in words is "one trillion, three hundred fifty-four billion, three hundred fifty-four million, two hundred fifty thousand, three hundred fifty-one".