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1354355041345 = 5270871008269
BaseRepresentation
bin10011101101010101110…
…110011110010001000001
311210110211022221122110121
4103231111312132101001
5134142204342310340
62514103200500241
7166564115622565
oct23552566362101
94713738848417
101354355041345
11482419127269
1219a59691a681
139a93b1b85b7
14497a044d6a5
152536acc294a
hex13b55d9e441

1354355041345 has 4 divisors (see below), whose sum is σ = 1625226049620. Its totient is φ = 1083484033072.

The previous prime is 1354355041327. The next prime is 1354355041447. The reversal of 1354355041345 is 5431405534531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 668353665841 + 686001375504 = 817529^2 + 828252^2 .

It is a cyclic number.

It is not a de Polignac number, because 1354355041345 - 229 = 1353818170433 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135435504130 + ... + 135435504139.

It is an arithmetic number, because the mean of its divisors is an integer number (406306512405).

Almost surely, 21354355041345 is an apocalyptic number.

It is an amenable number.

1354355041345 is a deficient number, since it is larger than the sum of its proper divisors (270871008275).

1354355041345 is an equidigital number, since it uses as much as digits as its factorization.

1354355041345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 270871008274.

The product of its (nonzero) digits is 1080000, while the sum is 43.

The spelling of 1354355041345 in words is "one trillion, three hundred fifty-four billion, three hundred fifty-five million, forty-one thousand, three hundred forty-five".

Divisors: 1 5 270871008269 1354355041345