Base | Representation |
---|---|
bin | 11110110010110110001001… |
… | …101101011011100001000110 |
3 | 122202112111201211210122101102 |
4 | 132302312021231123201012 |
5 | 120222433413104220200 |
6 | 1200014114413500102 |
7 | 40345615203415652 |
oct | 3662661155334106 |
9 | 582474654718342 |
10 | 135435514132550 |
11 | 3a176973a27555 |
12 | 132343877a1632 |
13 | 5a7568b8710a8 |
14 | 2563184607a62 |
15 | 109cec644e6d5 |
hex | 7b2d89b5b846 |
135435514132550 has 12 divisors (see below), whose sum is σ = 251910056286636. Its totient is φ = 54174205653000.
The previous prime is 135435514132493. The next prime is 135435514132573. The reversal of 135435514132550 is 55231415534531.
It is a junction number, because it is equal to n+sod(n) for n = 135435514132495 and 135435514132504.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1354355141276 + ... + 1354355141375.
It is an arithmetic number, because the mean of its divisors is an integer number (20992504690553).
Almost surely, 2135435514132550 is an apocalyptic number.
135435514132550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
135435514132550 is a deficient number, since it is larger than the sum of its proper divisors (116474542154086).
135435514132550 is a wasteful number, since it uses less digits than its factorization.
135435514132550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2708710282663 (or 2708710282658 counting only the distinct ones).
The product of its (nonzero) digits is 2700000, while the sum is 47.
The spelling of 135435514132550 in words is "one hundred thirty-five trillion, four hundred thirty-five billion, five hundred fourteen million, one hundred thirty-two thousand, five hundred fifty".
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