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135441041 is a prime number
BaseRepresentation
bin10000001001010…
…10101010010001
3100102212010011212
420010222222101
5234133103131
621234545505
73233141561
oct1004525221
9312763155
10135441041
116a4a894a
1239438295
13220a2238
1413db8da1
15bd55a2b
hex812aa91

135441041 has 2 divisors, whose sum is σ = 135441042. Its totient is φ = 135441040.

The previous prime is 135441037. The next prime is 135441073. The reversal of 135441041 is 140144531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 72318016 + 63123025 = 8504^2 + 7945^2 .

It is a cyclic number.

It is not a de Polignac number, because 135441041 - 22 = 135441037 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 135440998 and 135441016.

It is not a weakly prime, because it can be changed into another prime (135443041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67720520 + 67720521.

It is an arithmetic number, because the mean of its divisors is an integer number (67720521).

Almost surely, 2135441041 is an apocalyptic number.

It is an amenable number.

135441041 is a deficient number, since it is larger than the sum of its proper divisors (1).

135441041 is an equidigital number, since it uses as much as digits as its factorization.

135441041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 23.

The square root of 135441041 is about 11637.9139453770. The cubic root of 135441041 is about 513.5508208221.

Adding to 135441041 its reverse (140144531), we get a palindrome (275585572).

The spelling of 135441041 in words is "one hundred thirty-five million, four hundred forty-one thousand, forty-one".