Base | Representation |
---|---|
bin | 11001001110100101… |
… | …01010000011001110 |
3 | 1021221220121210000202 |
4 | 30213102222003032 |
5 | 210214242313032 |
6 | 10115545053502 |
7 | 656430662042 |
oct | 144722520316 |
9 | 37856553022 |
10 | 13544104142 |
11 | 58203259a8 |
12 | 275ba87292 |
13 | 137b02970a |
14 | 926b22022 |
15 | 5440ccd62 |
hex | 3274aa0ce |
13544104142 has 4 divisors (see below), whose sum is σ = 20316156216. Its totient is φ = 6772052070.
The previous prime is 13544104099. The next prime is 13544104157. The reversal of 13544104142 is 24140144531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24140144531 = 89 ⋅271237579.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3386026034 + ... + 3386026037.
It is an arithmetic number, because the mean of its divisors is an integer number (5079039054).
Almost surely, 213544104142 is an apocalyptic number.
13544104142 is a deficient number, since it is larger than the sum of its proper divisors (6772052074).
13544104142 is an equidigital number, since it uses as much as digits as its factorization.
13544104142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6772052073.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 13544104142 its reverse (24140144531), we get a palindrome (37684248673).
The spelling of 13544104142 in words is "thirteen billion, five hundred forty-four million, one hundred four thousand, one hundred forty-two".
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