135441513210143 has 4 divisors (see below), whose sum is σ = 154790300811600. Its totient is φ = 116092725608688.

The previous prime is 135441513210119. The next prime is 135441513210193. The reversal of 135441513210143 is 341012315144531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135441513210143 - 2⁸ = 135441513209887 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135441513210097 and 135441513210106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135441513210103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9674393800718 + ... + 9674393800731.

It is an arithmetic number, because the mean of its divisors is an integer number (38697575202900).

Almost surely, 2^{135441513210143} is an apocalyptic number.

135441513210143 is a deficient number, since it is larger than the sum of its proper divisors (19348787601457).

135441513210143 is an equidigital number, since it uses as much as digits as its factorization.

135441513210143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19348787601456.

The product of its (nonzero) digits is 86400, while the sum is 38.

Adding to 135441513210143 its reverse (341012315144531), we get a palindrome (476453828354674).

The spelling of 135441513210143 in words is "one hundred thirty-five trillion, four hundred forty-one billion, five hundred thirteen million, two hundred ten thousand, one hundred forty-three".