Base | Representation |
---|---|
bin | 11001001110100111… |
… | …11100110010011010 |
3 | 1021221221020222220022 |
4 | 30213103330302122 |
5 | 210214334134114 |
6 | 10120000230442 |
7 | 656433603053 |
oct | 144723746232 |
9 | 37857228808 |
10 | 13544443034 |
11 | 5820537581 |
12 | 276000b422 |
13 | 137b117a45 |
14 | 926bad72a |
15 | 54414848e |
hex | 3274fcc9a |
13544443034 has 8 divisors (see below), whose sum is σ = 20573837760. Its totient is φ = 6686497116.
The previous prime is 13544443009. The next prime is 13544443039. The reversal of 13544443034 is 43034444531.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×135444430342 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13544442985 and 13544443003.
It is not an unprimeable number, because it can be changed into a prime (13544443039) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42862004 + ... + 42862319.
It is an arithmetic number, because the mean of its divisors is an integer number (2571729720).
Almost surely, 213544443034 is an apocalyptic number.
13544443034 is a deficient number, since it is larger than the sum of its proper divisors (7029394726).
13544443034 is an equidigital number, since it uses as much as digits as its factorization.
13544443034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85724404.
The product of its (nonzero) digits is 138240, while the sum is 35.
Adding to 13544443034 its reverse (43034444531), we get a palindrome (56578887565).
The spelling of 13544443034 in words is "thirteen billion, five hundred forty-four million, four hundred forty-three thousand, thirty-four".
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