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135445212441263 is a prime number
BaseRepresentation
bin11110110010111111001011…
…110001100010101010101111
3122202120102202201212202212102
4132302333023301202222233
5120223113243341110023
61200022401022125315
740346410425605324
oct3662771361425257
9582512681782772
10135445212441263
113a17aaa041241a
121323623372083b
135a76575bba9ba
142563824676b4b
15109d392ab7628
hex7b2fcbc62aaf

135445212441263 has 2 divisors, whose sum is σ = 135445212441264. Its totient is φ = 135445212441262.

The previous prime is 135445212441193. The next prime is 135445212441271. The reversal of 135445212441263 is 362144212544531.

It is a strong prime.

It is an emirp because it is prime and its reverse (362144212544531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135445212441263 - 218 = 135445212179119 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135445212401263) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67722606220631 + 67722606220632.

It is an arithmetic number, because the mean of its divisors is an integer number (67722606220632).

Almost surely, 2135445212441263 is an apocalyptic number.

135445212441263 is a deficient number, since it is larger than the sum of its proper divisors (1).

135445212441263 is an equidigital number, since it uses as much as digits as its factorization.

135445212441263 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2764800, while the sum is 47.

Adding to 135445212441263 its reverse (362144212544531), we get a palindrome (497589424985794).

The spelling of 135445212441263 in words is "one hundred thirty-five trillion, four hundred forty-five billion, two hundred twelve million, four hundred forty-one thousand, two hundred sixty-three".