Base | Representation |
---|---|
bin | 11110110011000001000110… |
… | …110010001101000111001011 |
3 | 122202120122002120020020000221 |
4 | 132303001012302031013023 |
5 | 120223132010202301213 |
6 | 1200023341504010511 |
7 | 40346512525432531 |
oct | 3663010662150713 |
9 | 582518076206027 |
10 | 135447276212683 |
11 | 3a18095a356436 |
12 | 1323670a900a37 |
13 | 5a76814632816 |
14 | 256397c7b2151 |
15 | 109d463d7538d |
hex | 7b3046c8d1cb |
135447276212683 has 2 divisors, whose sum is σ = 135447276212684. Its totient is φ = 135447276212682.
The previous prime is 135447276212657. The next prime is 135447276212741. The reversal of 135447276212683 is 386212672744531.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135447276212683 is a prime.
It is not a weakly prime, because it can be changed into another prime (135447276212653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67723638106341 + 67723638106342.
It is an arithmetic number, because the mean of its divisors is an integer number (67723638106342).
Almost surely, 2135447276212683 is an apocalyptic number.
135447276212683 is a deficient number, since it is larger than the sum of its proper divisors (1).
135447276212683 is an equidigital number, since it uses as much as digits as its factorization.
135447276212683 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 81285120, while the sum is 61.
The spelling of 135447276212683 in words is "one hundred thirty-five trillion, four hundred forty-seven billion, two hundred seventy-six million, two hundred twelve thousand, six hundred eighty-three".
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