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1354500047 is a prime number
BaseRepresentation
bin101000010111100…
…0000011111001111
310111101201201202102
41100233000133033
510233223000142
6342223345315
745365026505
oct12057003717
93441651672
101354500047
11635641a2a
1231975223b
1318780a724
14cbc6a675
157dda8532
hex50bc07cf

1354500047 has 2 divisors, whose sum is σ = 1354500048. Its totient is φ = 1354500046.

The previous prime is 1354500011. The next prime is 1354500113. The reversal of 1354500047 is 7400054531.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1354500047 - 26 = 1354499983 is a prime.

It is a super-3 number, since 3×13545000473 (a number of 28 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1354499992 and 1354500019.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1354508047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677250023 + 677250024.

It is an arithmetic number, because the mean of its divisors is an integer number (677250024).

Almost surely, 21354500047 is an apocalyptic number.

1354500047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354500047 is an equidigital number, since it uses as much as digits as its factorization.

1354500047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8400, while the sum is 29.

The square root of 1354500047 is about 36803.5330776816. The cubic root of 1354500047 is about 1106.4361109542.

Adding to 1354500047 its reverse (7400054531), we get a palindrome (8754554578).

The spelling of 1354500047 in words is "one billion, three hundred fifty-four million, five hundred thousand, forty-seven".