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1354725443 is a prime number
BaseRepresentation
bin101000010111111…
…0111100001000011
310111102011011221102
41100233313201003
510233302203233
6342232245015
745366655601
oct12057674103
93442134842
101354725443
11635786305
1231984076b
131878891b6
14cbcc8871
157de001e8
hex50bf7843

1354725443 has 2 divisors, whose sum is σ = 1354725444. Its totient is φ = 1354725442.

The previous prime is 1354725439. The next prime is 1354725481. The reversal of 1354725443 is 3445274531.

It is an a-pointer prime, because the next prime (1354725481) can be obtained adding 1354725443 to its sum of digits (38).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1354725443 - 22 = 1354725439 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1354725397 and 1354725406.

It is not a weakly prime, because it can be changed into another prime (1354725413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677362721 + 677362722.

It is an arithmetic number, because the mean of its divisors is an integer number (677362722).

Almost surely, 21354725443 is an apocalyptic number.

1354725443 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354725443 is an equidigital number, since it uses as much as digits as its factorization.

1354725443 is an evil number, because the sum of its binary digits is even.

The product of its digits is 201600, while the sum is 38.

The square root of 1354725443 is about 36806.5951019651. The cubic root of 1354725443 is about 1106.4974798316.

Adding to 1354725443 its reverse (3445274531), we get a palindrome (4799999974).

The spelling of 1354725443 in words is "one billion, three hundred fifty-four million, seven hundred twenty-five thousand, four hundred forty-three".