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1354890256231 = 4057333963583
BaseRepresentation
bin10011101101110101110…
…000001001111101100111
311210112012122001101021011
4103231311300021331213
5134144303401144411
62514232240203051
7166613305105051
oct23556560117547
94715178041234
101354890256231
11482673256116
1219a706009487
139a9c50501b5
14498115708d1
152539cc94c21
hex13b75c09f67

1354890256231 has 4 divisors (see below), whose sum is σ = 1355224223872. Its totient is φ = 1354556288592.

The previous prime is 1354890256211. The next prime is 1354890256241. The reversal of 1354890256231 is 1326520984531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1354890256231 - 25 = 1354890256199 is a prime.

It is a super-2 number, since 2×13548902562312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1354890256211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166977735 + ... + 166985848.

It is an arithmetic number, because the mean of its divisors is an integer number (338806055968).

Almost surely, 21354890256231 is an apocalyptic number.

1354890256231 is a deficient number, since it is larger than the sum of its proper divisors (333967641).

1354890256231 is an equidigital number, since it uses as much as digits as its factorization.

1354890256231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 333967640.

The product of its (nonzero) digits is 1555200, while the sum is 49.

The spelling of 1354890256231 in words is "one trillion, three hundred fifty-four billion, eight hundred ninety million, two hundred fifty-six thousand, two hundred thirty-one".

Divisors: 1 4057 333963583 1354890256231