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135497609993 is a prime number
BaseRepresentation
bin111111000110001001…
…0010111001100001001
3110221202001122202202202
41332030102113030021
54204444342004433
6142125144005545
712534520452554
oct1761422271411
9427661582682
10135497609993
1152511960969
1222315a608b5
13ca14b5c6b5
1467b569d69b
1537d080eee8
hex1f8c497309

135497609993 has 2 divisors, whose sum is σ = 135497609994. Its totient is φ = 135497609992.

The previous prime is 135497609971. The next prime is 135497610029. The reversal of 135497609993 is 399906794531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93029880064 + 42467729929 = 305008^2 + 206077^2 .

It is an emirp because it is prime and its reverse (399906794531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135497609993 - 210 = 135497608969 is a prime.

It is not a weakly prime, because it can be changed into another prime (135497609963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67748804996 + 67748804997.

It is an arithmetic number, because the mean of its divisors is an integer number (67748804997).

Almost surely, 2135497609993 is an apocalyptic number.

It is an amenable number.

135497609993 is a deficient number, since it is larger than the sum of its proper divisors (1).

135497609993 is an equidigital number, since it uses as much as digits as its factorization.

135497609993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 49601160, while the sum is 65.

The spelling of 135497609993 in words is "one hundred thirty-five billion, four hundred ninety-seven million, six hundred nine thousand, nine hundred ninety-three".