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13550024041 is a prime number
BaseRepresentation
bin11001001111010010…
…01111010101101001
31021222022202112121021
430213221033111221
5210222301232131
610120320012441
7656532206161
oct144751172551
937868675537
1013550024041
1158236a9684
122761a61121
13137c320108
149278235a1
1554489be11
hex327a4f569

13550024041 has 2 divisors, whose sum is σ = 13550024042. Its totient is φ = 13550024040.

The previous prime is 13550023967. The next prime is 13550024057. The reversal of 13550024041 is 14042005531.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13188225600 + 361798441 = 114840^2 + 19021^2 .

It is a cyclic number.

It is not a de Polignac number, because 13550024041 - 217 = 13549892969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13550023997 and 13550024015.

It is not a weakly prime, because it can be changed into another prime (13550024141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775012020 + 6775012021.

It is an arithmetic number, because the mean of its divisors is an integer number (6775012021).

Almost surely, 213550024041 is an apocalyptic number.

It is an amenable number.

13550024041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13550024041 is an equidigital number, since it uses as much as digits as its factorization.

13550024041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 13550024041 its reverse (14042005531), we get a palindrome (27592029572).

The spelling of 13550024041 in words is "thirteen billion, five hundred fifty million, twenty-four thousand, forty-one".