Base | Representation |
---|---|
bin | 11001001111010100… |
… | …10110001001000011 |
3 | 1021222100022021102101 |
4 | 30213222112021003 |
5 | 210222340022201 |
6 | 10120330131231 |
7 | 656534524531 |
oct | 144752261103 |
9 | 37870267371 |
10 | 13550314051 |
11 | 582388755a |
12 | 2761b80b17 |
13 | 137c3c2111 |
14 | 92789b151 |
15 | 544907d01 |
hex | 327a96243 |
13550314051 has 4 divisors (see below), whose sum is σ = 13565059600. Its totient is φ = 13535568504.
The previous prime is 13550314013. The next prime is 13550314067. The reversal of 13550314051 is 15041305531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13550314051 - 219 = 13549789763 is a prime.
It is a super-2 number, since 2×135503140512 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13550314651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7371396 + ... + 7373233.
It is an arithmetic number, because the mean of its divisors is an integer number (3391264900).
Almost surely, 213550314051 is an apocalyptic number.
13550314051 is a deficient number, since it is larger than the sum of its proper divisors (14745549).
13550314051 is an equidigital number, since it uses as much as digits as its factorization.
13550314051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14745548.
The product of its (nonzero) digits is 4500, while the sum is 28.
Adding to 13550314051 its reverse (15041305531), we get a palindrome (28591619582).
The spelling of 13550314051 in words is "thirteen billion, five hundred fifty million, three hundred fourteen thousand, fifty-one".
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