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13550422351 = 27674897153
BaseRepresentation
bin11001001111010101…
…10000100101001111
31021222100111202222111
430213222300211033
5210222402003401
610120332324451
7656535455344
oct144752604517
937870452874
1013550422351
115823950964
122762013727
13137c42c4bb
149278c87cb
15544929e51
hex327ab094f

13550422351 has 4 divisors (see below), whose sum is σ = 13555322272. Its totient is φ = 13545522432.

The previous prime is 13550422253. The next prime is 13550422427. The reversal of 13550422351 is 15322405531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13550422351 - 29 = 13550421839 is a prime.

It is a super-2 number, since 2×135504223512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13550422651) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2445810 + ... + 2451343.

It is an arithmetic number, because the mean of its divisors is an integer number (3388830568).

Almost surely, 213550422351 is an apocalyptic number.

13550422351 is a deficient number, since it is larger than the sum of its proper divisors (4899921).

13550422351 is an equidigital number, since it uses as much as digits as its factorization.

13550422351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4899920.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 13550422351 its reverse (15322405531), we get a palindrome (28872827882).

The spelling of 13550422351 in words is "thirteen billion, five hundred fifty million, four hundred twenty-two thousand, three hundred fifty-one".

Divisors: 1 2767 4897153 13550422351