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135504703 is a prime number
BaseRepresentation
bin10000001001110…
…10001100111111
3100102222100111201
420010322030333
5234142122303
621240200331
73233525305
oct1004721477
9312870451
10135504703
116a541764
12394690a7
13220c51c9
1413dd4275
15bd6981d
hex813a33f

135504703 has 2 divisors, whose sum is σ = 135504704. Its totient is φ = 135504702.

The previous prime is 135504643. The next prime is 135504709. The reversal of 135504703 is 307405531.

135504703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (307405531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135504703 - 217 = 135373631 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135504709) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67752351 + 67752352.

It is an arithmetic number, because the mean of its divisors is an integer number (67752352).

Almost surely, 2135504703 is an apocalyptic number.

135504703 is a deficient number, since it is larger than the sum of its proper divisors (1).

135504703 is an equidigital number, since it uses as much as digits as its factorization.

135504703 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6300, while the sum is 28.

The square root of 135504703 is about 11640.6487362174. The cubic root of 135504703 is about 513.6312704678.

The spelling of 135504703 in words is "one hundred thirty-five million, five hundred four thousand, seven hundred three".