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13550502389 is a prime number
BaseRepresentation
bin11001001111010110…
…00100000111110101
31021222100122211202212
430213223010013311
5210222412034024
610120334143205
7656536240604
oct144753040765
937870584685
1013550502389
1158239a6006
122762051b05
13137c459a68
14927909a3b
15544943a0e
hex327ac41f5

13550502389 has 2 divisors, whose sum is σ = 13550502390. Its totient is φ = 13550502388.

The previous prime is 13550502379. The next prime is 13550502467. The reversal of 13550502389 is 98320505531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7807136164 + 5743366225 = 88358^2 + 75785^2 .

It is a cyclic number.

It is not a de Polignac number, because 13550502389 - 24 = 13550502373 is a prime.

It is a super-2 number, since 2×135505023892 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13550502379) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775251194 + 6775251195.

It is an arithmetic number, because the mean of its divisors is an integer number (6775251195).

Almost surely, 213550502389 is an apocalyptic number.

It is an amenable number.

13550502389 is a deficient number, since it is larger than the sum of its proper divisors (1).

13550502389 is an equidigital number, since it uses as much as digits as its factorization.

13550502389 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 41.

The spelling of 13550502389 in words is "thirteen billion, five hundred fifty million, five hundred two thousand, three hundred eighty-nine".