Base | Representation |
---|---|
bin | 111111000110010111… |
… | …0111100011000001111 |
3 | 110221202120202102100111 |
4 | 1332030232330120033 |
5 | 4210003301233401 |
6 | 142130012340451 |
7 | 12534641236303 |
oct | 1761456743017 |
9 | 427676672314 |
10 | 135505102351 |
11 | 52516108aa3 |
12 | 22318474727 |
13 | ca16583a48 |
14 | 67b668dd03 |
15 | 37d12dee51 |
hex | 1f8cbbc60f |
135505102351 has 2 divisors, whose sum is σ = 135505102352. Its totient is φ = 135505102350.
The previous prime is 135505102339. The next prime is 135505102391. The reversal of 135505102351 is 153201505531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135505102351 - 25 = 135505102319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135505102391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67752551175 + 67752551176.
It is an arithmetic number, because the mean of its divisors is an integer number (67752551176).
Almost surely, 2135505102351 is an apocalyptic number.
135505102351 is a deficient number, since it is larger than the sum of its proper divisors (1).
135505102351 is an equidigital number, since it uses as much as digits as its factorization.
135505102351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11250, while the sum is 31.
Adding to 135505102351 its reverse (153201505531), we get a palindrome (288706607882).
The spelling of 135505102351 in words is "one hundred thirty-five billion, five hundred five million, one hundred two thousand, three hundred fifty-one".
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