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135510104281 is a prime number
BaseRepresentation
bin111111000110100001…
…0000001100011011001
3110221202221011112201011
41332031002001203121
54210011041314111
6142130311453521
712535031611216
oct1761502014331
9427687145634
10135510104281
1152518a15022
122231a0872a1
13ca17615676
1467b71d2b0d
1537d197c021
hex1f8d0818d9

135510104281 has 2 divisors, whose sum is σ = 135510104282. Its totient is φ = 135510104280.

The previous prime is 135510104243. The next prime is 135510104333. The reversal of 135510104281 is 182401015531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114836265625 + 20673838656 = 338875^2 + 143784^2 .

It is a cyclic number.

It is not a de Polignac number, because 135510104281 - 219 = 135509579993 is a prime.

It is a super-2 number, since 2×1355101042812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135510104581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67755052140 + 67755052141.

It is an arithmetic number, because the mean of its divisors is an integer number (67755052141).

Almost surely, 2135510104281 is an apocalyptic number.

It is an amenable number.

135510104281 is a deficient number, since it is larger than the sum of its proper divisors (1).

135510104281 is an equidigital number, since it uses as much as digits as its factorization.

135510104281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 31.

The spelling of 135510104281 in words is "one hundred thirty-five billion, five hundred ten million, one hundred four thousand, two hundred eighty-one".