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135510320255033 is a prime number
BaseRepresentation
bin11110110011111011110100…
…100000001001000000111001
3122202210122211012201101212102
4132303323310200021000321
5120230200113441130113
61200112325352353145
740354204030105343
oct3663736440110071
9582718735641772
10135510320255033
113a1a5671045579
12132469840a57b5
135a7c7509249a9
142566a3d654293
15109ee0396b758
hex7b3ef4809039

135510320255033 has 2 divisors, whose sum is σ = 135510320255034. Its totient is φ = 135510320255032.

The previous prime is 135510320255017. The next prime is 135510320255117. The reversal of 135510320255033 is 330552023015531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129706860987664 + 5803459267369 = 11388892^2 + 2409037^2 .

It is a cyclic number.

It is not a de Polignac number, because 135510320255033 - 24 = 135510320255017 is a prime.

It is a super-3 number, since 3×1355103202550333 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (135510320254033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67755160127516 + 67755160127517.

It is an arithmetic number, because the mean of its divisors is an integer number (67755160127517).

Almost surely, 2135510320255033 is an apocalyptic number.

It is an amenable number.

135510320255033 is a deficient number, since it is larger than the sum of its proper divisors (1).

135510320255033 is an equidigital number, since it uses as much as digits as its factorization.

135510320255033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 202500, while the sum is 38.

The spelling of 135510320255033 in words is "one hundred thirty-five trillion, five hundred ten billion, three hundred twenty million, two hundred fifty-five thousand, thirty-three".