Base | Representation |
---|---|
bin | 1100010100110001111100… |
… | …0001010011011010111111 |
3 | 1202222110212101212221102121 |
4 | 3011030133001103122333 |
5 | 3234010214404114041 |
6 | 44453150411503411 |
7 | 2566015636434136 |
oct | 305143701233277 |
9 | 52873771787377 |
10 | 13551142254271 |
11 | 4355009585836 |
12 | 162a376157b67 |
13 | 773b373cc4bb |
14 | 34bc4355691d |
15 | 18776a0907d1 |
hex | c531f0536bf |
13551142254271 has 2 divisors, whose sum is σ = 13551142254272. Its totient is φ = 13551142254270.
The previous prime is 13551142254233. The next prime is 13551142254311. The reversal of 13551142254271 is 17245224115531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13551142254271 - 211 = 13551142252223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13551142654271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775571127135 + 6775571127136.
It is an arithmetic number, because the mean of its divisors is an integer number (6775571127136).
Almost surely, 213551142254271 is an apocalyptic number.
13551142254271 is a deficient number, since it is larger than the sum of its proper divisors (1).
13551142254271 is an equidigital number, since it uses as much as digits as its factorization.
13551142254271 is an evil number, because the sum of its binary digits is even.
The product of its digits is 336000, while the sum is 43.
The spelling of 13551142254271 in words is "thirteen trillion, five hundred fifty-one billion, one hundred forty-two million, two hundred fifty-four thousand, two hundred seventy-one".
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