Base | Representation |
---|---|
bin | 10011101110000011100… |
… | …010010101100000111011 |
3 | 11210112210202012112001021 |
4 | 103232003202111200323 |
5 | 134200242101431210 |
6 | 2514311221003311 |
7 | 166622113551424 |
oct | 23560342254073 |
9 | 4715722175037 |
10 | 1355121514555 |
11 | 4827818489a6 |
12 | 19a76b553537 |
13 | 9aa30c30143 |
14 | 4983416c64b |
15 | 253b3225bda |
hex | 13b8389583b |
1355121514555 has 4 divisors (see below), whose sum is σ = 1626145817472. Its totient is φ = 1084097211640.
The previous prime is 1355121514553. The next prime is 1355121514559. The reversal of 1355121514555 is 5554151215531.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1355121514555 - 21 = 1355121514553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1355121514553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135512151451 + ... + 135512151460.
It is an arithmetic number, because the mean of its divisors is an integer number (406536454368).
Almost surely, 21355121514555 is an apocalyptic number.
1355121514555 is a deficient number, since it is larger than the sum of its proper divisors (271024302917).
1355121514555 is an equidigital number, since it uses as much as digits as its factorization.
1355121514555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 271024302916.
The product of its digits is 375000, while the sum is 43.
The spelling of 1355121514555 in words is "one trillion, three hundred fifty-five billion, one hundred twenty-one million, five hundred fourteen thousand, five hundred fifty-five".
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