1355124040373 has 2 divisors, whose sum is σ = 1355124040374. Its totient is φ = 1355124040372.

The previous prime is 1355124040339. The next prime is 1355124040427. The reversal of 1355124040373 is 3730404215531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 835099890244 + 520024150129 = 913838^2 + 721127^2 .

It is a cyclic number.

It is not a de Polignac number, because 1355124040373 - 2⁸ = 1355124040117 is a prime.

It is a super-2 number, since 2×1355124040373² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1355124040873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677562020186 + 677562020187.

It is an arithmetic number, because the mean of its divisors is an integer number (677562020187).

Almost surely, 2^{1355124040373} is an apocalyptic number.

It is an amenable number.

1355124040373 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355124040373 is an equidigital number, since it uses as much as digits as its factorization.

1355124040373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 38.

The spelling of 1355124040373 in words is "one trillion, three hundred fifty-five billion, one hundred twenty-four million, forty thousand, three hundred seventy-three".