Base | Representation |
---|---|
bin | 111111000110100111… |
… | …0101001101100100101 |
3 | 110221210011101201101112 |
4 | 1332031032221230211 |
5 | 4210012413230222 |
6 | 142130510434405 |
7 | 12535102005632 |
oct | 1761516515445 |
9 | 427704351345 |
10 | 135513414437 |
11 | 5251a875a95 |
12 | 2231b202a05 |
13 | ca1820423b |
14 | 67b7815189 |
15 | 37d1dd2be2 |
hex | 1f8d3a9b25 |
135513414437 has 2 divisors, whose sum is σ = 135513414438. Its totient is φ = 135513414436.
The previous prime is 135513414427. The next prime is 135513414451. The reversal of 135513414437 is 734414315531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72425036161 + 63088378276 = 269119^2 + 251174^2 .
It is a cyclic number.
It is not a de Polignac number, because 135513414437 - 28 = 135513414181 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135513414394 and 135513414403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135513414427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67756707218 + 67756707219.
It is an arithmetic number, because the mean of its divisors is an integer number (67756707219).
Almost surely, 2135513414437 is an apocalyptic number.
It is an amenable number.
135513414437 is a deficient number, since it is larger than the sum of its proper divisors (1).
135513414437 is an equidigital number, since it uses as much as digits as its factorization.
135513414437 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 302400, while the sum is 41.
Adding to 135513414437 its reverse (734414315531), we get a palindrome (869927729968).
The spelling of 135513414437 in words is "one hundred thirty-five billion, five hundred thirteen million, four hundred fourteen thousand, four hundred thirty-seven".
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