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135514303 = 294672907
BaseRepresentation
bin10000001001111…
…00100010111111
3100102222211200021
420010330202333
5234142424203
621240313011
73233565301
oct1004744277
9312884607
10135514303
116a5489a1
1239472767
13220c96a2
1413dd7971
15bd6c5bd
hex813c8bf

135514303 has 4 divisors (see below), whose sum is σ = 140187240. Its totient is φ = 130841368.

The previous prime is 135514283. The next prime is 135514331. The reversal of 135514303 is 303415531.

135514303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135514303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135514343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2336425 + ... + 2336482.

It is an arithmetic number, because the mean of its divisors is an integer number (35046810).

Almost surely, 2135514303 is an apocalyptic number.

135514303 is a deficient number, since it is larger than the sum of its proper divisors (4672937).

135514303 is an equidigital number, since it uses as much as digits as its factorization.

135514303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4672936.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 135514303 is about 11641.0610770668. The cubic root of 135514303 is about 513.6433997978.

Adding to 135514303 its reverse (303415531), we get a palindrome (438929834).

The spelling of 135514303 in words is "one hundred thirty-five million, five hundred fourteen thousand, three hundred three".

Divisors: 1 29 4672907 135514303