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135516629427409 is a prime number
BaseRepresentation
bin11110110100000001101100…
…100011101110010011010001
3122202211021002220112120022101
4132310001230203232103101
5120230301024113134114
61200115251412040401
740354516260145036
oct3664015443562321
9582737086476271
10135516629427409
113a1a830944511a
1213248045003101
135a80217a80499
14256707b54338d
1510a01727c5d74
hex7b406c8ee4d1

135516629427409 has 2 divisors, whose sum is σ = 135516629427410. Its totient is φ = 135516629427408.

The previous prime is 135516629427373. The next prime is 135516629427433. The reversal of 135516629427409 is 904724926615531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68338279289809 + 67178350137600 = 8266697^2 + 8196240^2 .

It is a cyclic number.

It is not a de Polignac number, because 135516629427409 - 241 = 133317606171857 is a prime.

It is not a weakly prime, because it can be changed into another prime (135516629428409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67758314713704 + 67758314713705.

It is an arithmetic number, because the mean of its divisors is an integer number (67758314713705).

Almost surely, 2135516629427409 is an apocalyptic number.

It is an amenable number.

135516629427409 is a deficient number, since it is larger than the sum of its proper divisors (1).

135516629427409 is an equidigital number, since it uses as much as digits as its factorization.

135516629427409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97977600, while the sum is 64.

The spelling of 135516629427409 in words is "one hundred thirty-five trillion, five hundred sixteen billion, six hundred twenty-nine million, four hundred twenty-seven thousand, four hundred nine".