1355175500117 has 2 divisors, whose sum is σ = 1355175500118. Its totient is φ = 1355175500116.

The previous prime is 1355175500087. The next prime is 1355175500177. The reversal of 1355175500117 is 7110055715531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1351094717956 + 4080782161 = 1162366^2 + 63881^2 .

It is a cyclic number.

It is not a de Polignac number, because 1355175500117 - 2¹⁶ = 1355175434581 is a prime.

It is a super-2 number, since 2×1355175500117² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1355175500177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677587750058 + 677587750059.

It is an arithmetic number, because the mean of its divisors is an integer number (677587750059).

Almost surely, 2^{1355175500117} is an apocalyptic number.

It is an amenable number.

1355175500117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355175500117 is an equidigital number, since it uses as much as digits as its factorization.

1355175500117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 91875, while the sum is 41.

The spelling of 1355175500117 in words is "one trillion, three hundred fifty-five billion, one hundred seventy-five million, five hundred thousand, one hundred seventeen".