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13552106035333 is a prime number
BaseRepresentation
bin1100010100110101100001…
…1101110101100010000101
31202222120100120102002111111
43011031120131311202011
53234014203121112313
644453430201005021
72566051551435355
oct305153035654205
952876316362444
1013552106035333
114355463610808
12162a5a4a83771
13773c5bc97b58
1434bcd5556b65
151877c49ba43d
hexc5358775885

13552106035333 has 2 divisors, whose sum is σ = 13552106035334. Its totient is φ = 13552106035332.

The previous prime is 13552106035301. The next prime is 13552106035381. The reversal of 13552106035333 is 33353060125531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13425240418209 + 126865617124 = 3664047^2 + 356182^2 .

It is a cyclic number.

It is not a de Polignac number, because 13552106035333 - 25 = 13552106035301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13552106035733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6776053017666 + 6776053017667.

It is an arithmetic number, because the mean of its divisors is an integer number (6776053017667).

Almost surely, 213552106035333 is an apocalyptic number.

It is an amenable number.

13552106035333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13552106035333 is an equidigital number, since it uses as much as digits as its factorization.

13552106035333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 364500, while the sum is 40.

The spelling of 13552106035333 in words is "thirteen trillion, five hundred fifty-two billion, one hundred six million, thirty-five thousand, three hundred thirty-three".