Search a number
-
+
13552144214 = 27968010301
BaseRepresentation
bin11001001111100010…
…10100111101010110
31021222110202020221012
430213301110331112
5210223322103324
610120433252222
7656556216350
oct144761247526
937873666835
1013552144214
115824917594
122762704072
13137c8b315b
14927c160d0
15544b6a20e
hex327c54f56

13552144214 has 8 divisors (see below), whose sum is σ = 23232247248. Its totient is φ = 5808061800.

The previous prime is 13552144189. The next prime is 13552144259. The reversal of 13552144214 is 41244125531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×135521442143 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 484005137 + ... + 484005164.

It is an arithmetic number, because the mean of its divisors is an integer number (2904030906).

Almost surely, 213552144214 is an apocalyptic number.

13552144214 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

13552144214 is a deficient number, since it is larger than the sum of its proper divisors (9680103034).

13552144214 is an equidigital number, since it uses as much as digits as its factorization.

13552144214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 968010310.

The product of its digits is 19200, while the sum is 32.

Adding to 13552144214 its reverse (41244125531), we get a palindrome (54796269745).

The spelling of 13552144214 in words is "thirteen billion, five hundred fifty-two million, one hundred forty-four thousand, two hundred fourteen".

Divisors: 1 2 7 14 968010301 1936020602 6776072107 13552144214