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135522334321 = 1112320212211
BaseRepresentation
bin111111000110111000…
…0101011011001110001
3110221210210011220011121
41332031300223121301
54210022204144241
6142131425542241
712535240556263
oct1761560533161
9427723156147
10135522334321
11525249086a0
12223221a4981
13ca1a00828a
1467b8a97b33
1537d2a95ad1
hex1f8dc2b671

135522334321 has 4 divisors (see below), whose sum is σ = 147842546544. Its totient is φ = 123202122100.

The previous prime is 135522334319. The next prime is 135522334429. The reversal of 135522334321 is 123433225531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 135522334321 - 21 = 135522334319 is a prime.

It is not an unprimeable number, because it can be changed into a prime (135522334121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6160106095 + ... + 6160106116.

It is an arithmetic number, because the mean of its divisors is an integer number (36960636636).

Almost surely, 2135522334321 is an apocalyptic number.

135522334321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

135522334321 is a deficient number, since it is larger than the sum of its proper divisors (12320212223).

135522334321 is a wasteful number, since it uses less digits than its factorization.

135522334321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12320212222.

The product of its digits is 64800, while the sum is 34.

Adding to 135522334321 its reverse (123433225531), we get a palindrome (258955559852).

The spelling of 135522334321 in words is "one hundred thirty-five billion, five hundred twenty-two million, three hundred thirty-four thousand, three hundred twenty-one".

Divisors: 1 11 12320212211 135522334321