Base | Representation |
---|---|
bin | 11001001111100100… |
… | …10010000110101011 |
3 | 1021222111012222111020 |
4 | 30213302102012223 |
5 | 210223403112132 |
6 | 10120442503523 |
7 | 656561311500 |
oct | 144762220653 |
9 | 37874188436 |
10 | 13552394667 |
11 | 5824a78779 |
12 | 2762804ba3 |
13 | 137c970156 |
14 | 927c7d4a7 |
15 | 544bb952c |
hex | 327c921ab |
13552394667 has 48 divisors (see below), whose sum is σ = 21541512960. Its totient is φ = 7552657728.
The previous prime is 13552394591. The next prime is 13552394671. The reversal of 13552394667 is 76649325531.
It is a happy number.
13552394667 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13552394667 - 27 = 13552394539 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13552394267) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5807833 + ... + 5810165.
It is an arithmetic number, because the mean of its divisors is an integer number (448781520).
Almost surely, 213552394667 is an apocalyptic number.
13552394667 is a deficient number, since it is larger than the sum of its proper divisors (7989118293).
13552394667 is a wasteful number, since it uses less digits than its factorization.
13552394667 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3312 (or 3305 counting only the distinct ones).
The product of its digits is 4082400, while the sum is 51.
The spelling of 13552394667 in words is "thirteen billion, five hundred fifty-two million, three hundred ninety-four thousand, six hundred sixty-seven".
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