13552404010141 has 4 divisors (see below), whose sum is σ = 13554255185884. Its totient is φ = 13550552834400.

The previous prime is 13552404010109. The next prime is 13552404010231. The reversal of 13552404010141 is 14101040425531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2158093212025 + 11394310798116 = 1469045^2 + 3375546^2 .

It is a cyclic number.

It is not a de Polignac number, because 13552404010141 - 2⁵ = 13552404010109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13552404070141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 925576890 + ... + 925591531.

It is an arithmetic number, because the mean of its divisors is an integer number (3388563796471).

Almost surely, 2^{13552404010141} is an apocalyptic number.

It is an amenable number.

13552404010141 is a deficient number, since it is larger than the sum of its proper divisors (1851175743).

13552404010141 is an equidigital number, since it uses as much as digits as its factorization.

13552404010141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1851175742.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 13552404010141 its reverse (14101040425531), we get a palindrome (27653444435672).

The spelling of 13552404010141 in words is "thirteen trillion, five hundred fifty-two billion, four hundred four million, ten thousand, one hundred forty-one".