Base | Representation |
---|---|
bin | 10011101110001010101… |
… | …011110110101010101001 |
3 | 11210120010002212212202110 |
4 | 103232022223312222221 |
5 | 134201013302401103 |
6 | 2514331143352533 |
7 | 166625101154043 |
oct | 23561253665251 |
9 | 4716102785673 |
10 | 1355241450153 |
11 | 482833516328 |
12 | 19a7a3752749 |
13 | 9aa4ca33956 |
14 | 4984606ca93 |
15 | 253bda17403 |
hex | 13b8aaf6aa9 |
1355241450153 has 8 divisors (see below), whose sum is σ = 1885553322048. Its totient is φ = 864211939184.
The previous prime is 1355241450149. The next prime is 1355241450191. The reversal of 1355241450153 is 3510541425531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1355241450153 - 22 = 1355241450149 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1355241450193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9820590150 + ... + 9820590287.
It is an arithmetic number, because the mean of its divisors is an integer number (235694165256).
Almost surely, 21355241450153 is an apocalyptic number.
It is an amenable number.
1355241450153 is a deficient number, since it is larger than the sum of its proper divisors (530311871895).
1355241450153 is a wasteful number, since it uses less digits than its factorization.
1355241450153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19641180463.
The product of its (nonzero) digits is 180000, while the sum is 39.
Adding to 1355241450153 its reverse (3510541425531), we get a palindrome (4865782875684).
The spelling of 1355241450153 in words is "one trillion, three hundred fifty-five billion, two hundred forty-one million, four hundred fifty thousand, one hundred fifty-three".
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