Base | Representation |
---|---|
bin | 10011101110001100000… |
… | …010110010110111101110 |
3 | 11210120011200202210002212 |
4 | 103232030002302313232 |
5 | 134201040121204014 |
6 | 2514333320050422 |
7 | 166625465656046 |
oct | 23561402626756 |
9 | 4716150683085 |
10 | 1355264241134 |
11 | 482845372551 |
12 | 19a7ab303a12 |
13 | 9aa5468353b |
14 | 498490c2726 |
15 | 253c0a1a23e |
hex | 13b8c0b2dee |
1355264241134 has 4 divisors (see below), whose sum is σ = 2032896361704. Its totient is φ = 677632120566.
The previous prime is 1355264241127. The next prime is 1355264241173. The reversal of 1355264241134 is 4311424625531.
It is a semiprime because it is the product of two primes.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1355264241091 and 1355264241100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 338816060282 + ... + 338816060285.
It is an arithmetic number, because the mean of its divisors is an integer number (508224090426).
Almost surely, 21355264241134 is an apocalyptic number.
1355264241134 is a deficient number, since it is larger than the sum of its proper divisors (677632120570).
1355264241134 is an equidigital number, since it uses as much as digits as its factorization.
1355264241134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 677632120569.
The product of its digits is 345600, while the sum is 41.
Adding to 1355264241134 its reverse (4311424625531), we get a palindrome (5666688866665).
The spelling of 1355264241134 in words is "one trillion, three hundred fifty-five billion, two hundred sixty-four million, two hundred forty-one thousand, one hundred thirty-four".
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