Base | Representation |
---|---|
bin | 11110110100001111110000… |
… | …111000010000011010100011 |
3 | 122202212201002121000211012122 |
4 | 132310033300320100122203 |
5 | 120231022442440220134 |
6 | 1200130230314014455 |
7 | 40355562502401245 |
oct | 3664176070203243 |
9 | 582781077024178 |
10 | 135531734304419 |
11 | 3a20375a789852 |
12 | 1324ab5b71742b |
13 | 5a81784259b2b |
14 | 2567ab1668095 |
15 | 10a075890502e |
hex | 7b43f0e106a3 |
135531734304419 has 2 divisors, whose sum is σ = 135531734304420. Its totient is φ = 135531734304418.
The previous prime is 135531734304403. The next prime is 135531734304469. The reversal of 135531734304419 is 914403437135531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135531734304419 - 24 = 135531734304403 is a prime.
It is a super-2 number, since 2×1355317343044192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (135531734304469) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67765867152209 + 67765867152210.
It is an arithmetic number, because the mean of its divisors is an integer number (67765867152210).
Almost surely, 2135531734304419 is an apocalyptic number.
135531734304419 is a deficient number, since it is larger than the sum of its proper divisors (1).
135531734304419 is an equidigital number, since it uses as much as digits as its factorization.
135531734304419 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8164800, while the sum is 53.
The spelling of 135531734304419 in words is "one hundred thirty-five trillion, five hundred thirty-one billion, seven hundred thirty-four million, three hundred four thousand, four hundred nineteen".
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