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13553255024331 = 311410704697707
BaseRepresentation
bin1100010100111001110011…
…1100111000011011001011
31202222200022122102210002120
43011032130330320123023
53234024031241234311
644454140203502323
72566122202615461
oct305163474703313
952880278383076
1013553255024331
1143559a31461a0
12162a8658279a3
137740b303b9b9
1434bda3da8831
151878407cb706
hexc539cf386cb

13553255024331 has 8 divisors (see below), whose sum is σ = 19713825489984. Its totient is φ = 8214093954120.

The previous prime is 13553255024279. The next prime is 13553255024369. The reversal of 13553255024331 is 13342055235531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13553255024331 - 222 = 13553250830027 is a prime.

It is a super-2 number, since 2×135532550243312 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13553255024831) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 205352348821 + ... + 205352348886.

It is an arithmetic number, because the mean of its divisors is an integer number (2464228186248).

Almost surely, 213553255024331 is an apocalyptic number.

13553255024331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13553255024331 is a deficient number, since it is larger than the sum of its proper divisors (6160570465653).

13553255024331 is a wasteful number, since it uses less digits than its factorization.

13553255024331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 410704697721.

The product of its (nonzero) digits is 810000, while the sum is 42.

The spelling of 13553255024331 in words is "thirteen trillion, five hundred fifty-three billion, two hundred fifty-five million, twenty-four thousand, three hundred thirty-one".

Divisors: 1 3 11 33 410704697707 1232114093121 4517751674777 13553255024331