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13553440151 = 41330571711
BaseRepresentation
bin11001001111101100…
…10001010110010111
31021222120012002121212
430213312101112113
5210224140041101
610120521132035
7656603224526
oct144766212627
937876162555
1013553440151
115825622209
12276302a01b
13137cc47c94
149280724bd
15544d241bb
hex327d91597

13553440151 has 4 divisors (see below), whose sum is σ = 13884011904. Its totient is φ = 13222868400.

The previous prime is 13553440129. The next prime is 13553440171. The reversal of 13553440151 is 15104435531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13553440151 - 230 = 12479698327 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13553440171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165285815 + ... + 165285896.

It is an arithmetic number, because the mean of its divisors is an integer number (3471002976).

Almost surely, 213553440151 is an apocalyptic number.

13553440151 is a deficient number, since it is larger than the sum of its proper divisors (330571753).

13553440151 is an equidigital number, since it uses as much as digits as its factorization.

13553440151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 330571752.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 13553440151 its reverse (15104435531), we get a palindrome (28657875682).

The spelling of 13553440151 in words is "thirteen billion, five hundred fifty-three million, four hundred forty thousand, one hundred fifty-one".

Divisors: 1 41 330571711 13553440151