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135540021211 = 749938803327
BaseRepresentation
bin111111000111011010…
…0001001011111011011
3110221212000110111000121
41332032310021133123
54210041221134321
6142133301014111
712535544112460
oct1761664113733
9427760414017
10135540021211
1152533899061
12223280b4337
13ca2088b8aa
1467bb17d667
1537d43db441
hex1f8ed097db

135540021211 has 8 divisors (see below), whose sum is σ = 155213312000. Its totient is φ = 115944338088.

The previous prime is 135540021173. The next prime is 135540021283. The reversal of 135540021211 is 112120045531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 135540021211 - 29 = 135540020699 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135540081211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19398171 + ... + 19405156.

It is an arithmetic number, because the mean of its divisors is an integer number (19401664000).

Almost surely, 2135540021211 is an apocalyptic number.

135540021211 is a deficient number, since it is larger than the sum of its proper divisors (19673290789).

135540021211 is an equidigital number, since it uses as much as digits as its factorization.

135540021211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38803833.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 135540021211 its reverse (112120045531), we get a palindrome (247660066742).

The spelling of 135540021211 in words is "one hundred thirty-five billion, five hundred forty million, twenty-one thousand, two hundred eleven".

Divisors: 1 7 499 3493 38803327 271623289 19362860173 135540021211