Base | Representation |
---|---|
bin | 10011101110010100001… |
… | …010010110100011001111 |
3 | 11210120112012001101211212 |
4 | 103232110022112203033 |
5 | 134201330003040030 |
6 | 2514355023205035 |
7 | 166632041435246 |
oct | 23562412264317 |
9 | 4716465041755 |
10 | 1355400440015 |
11 | 482905238806 |
12 | 19a828a4677b |
13 | 9aa7695c6ab |
14 | 4985d21795d |
15 | 253cc970595 |
hex | 13b942968cf |
1355400440015 has 16 divisors (see below), whose sum is σ = 1628696481408. Its totient is φ = 1082843457696.
The previous prime is 1355400439973. The next prime is 1355400440039. The reversal of 1355400440015 is 5100440045531.
It is a cyclic number.
It is not a de Polignac number, because 1355400440015 - 218 = 1355400177871 is a prime.
It is a super-2 number, since 2×13554004400152 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31913384 + ... + 31955826.
It is an arithmetic number, because the mean of its divisors is an integer number (101793530088).
Almost surely, 21355400440015 is an apocalyptic number.
1355400440015 is a deficient number, since it is larger than the sum of its proper divisors (273296041393).
1355400440015 is an equidigital number, since it uses as much as digits as its factorization.
1355400440015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50998.
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 1355400440015 its reverse (5100440045531), we get a palindrome (6455840485546).
The spelling of 1355400440015 in words is "one trillion, three hundred fifty-five billion, four hundred million, four hundred forty thousand, fifteen".
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