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1355403121 is a prime number
BaseRepresentation
bin101000011001001…
…1100111101110001
310111110102121112121
41100302130331301
510233440344441
6342254554241
745405510412
oct12062347561
93443377477
101355403121
116360a9476
12319b08981
13187a657a7
14cc023809
157ded5dd1
hex50c9cf71

1355403121 has 2 divisors, whose sum is σ = 1355403122. Its totient is φ = 1355403120.

The previous prime is 1355403113. The next prime is 1355403151. The reversal of 1355403121 is 1213045531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1237984225 + 117418896 = 35185^2 + 10836^2 .

It is a cyclic number.

It is not a de Polignac number, because 1355403121 - 23 = 1355403113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1355403151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677701560 + 677701561.

It is an arithmetic number, because the mean of its divisors is an integer number (677701561).

Almost surely, 21355403121 is an apocalyptic number.

It is an amenable number.

1355403121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355403121 is an equidigital number, since it uses as much as digits as its factorization.

1355403121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 25.

The square root of 1355403121 is about 36815.7998826591. The cubic root of 1355403121 is about 1106.6819511586.

Adding to 1355403121 its reverse (1213045531), we get a palindrome (2568448652).

The spelling of 1355403121 in words is "one billion, three hundred fifty-five million, four hundred three thousand, one hundred twenty-one".