Base | Representation |
---|---|
bin | 10011101110010100110… |
… | …010101001100000011111 |
3 | 11210120112220221002010012 |
4 | 103232110302221200133 |
5 | 134201340204102143 |
6 | 2514400041433435 |
7 | 166632230302331 |
oct | 23562462514037 |
9 | 4716486832105 |
10 | 1355411003423 |
11 | 4829101a31a4 |
12 | 19a83049b87b |
13 | 9aa78bba829 |
14 | 498607a7451 |
15 | 253cd85a418 |
hex | 13b94ca981f |
1355411003423 has 2 divisors, whose sum is σ = 1355411003424. Its totient is φ = 1355411003422.
The previous prime is 1355411003381. The next prime is 1355411003473. The reversal of 1355411003423 is 3243001145531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1355411003423 - 240 = 255899375647 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1355411003423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1355411003473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677705501711 + 677705501712.
It is an arithmetic number, because the mean of its divisors is an integer number (677705501712).
Almost surely, 21355411003423 is an apocalyptic number.
1355411003423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355411003423 is an equidigital number, since it uses as much as digits as its factorization.
1355411003423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 1355411003423 its reverse (3243001145531), we get a palindrome (4598412148954).
The spelling of 1355411003423 in words is "one trillion, three hundred fifty-five billion, four hundred eleven million, three thousand, four hundred twenty-three".
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