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1355425122143 = 5472477925269
BaseRepresentation
bin10011101110010101101…
…000100000011101011111
311210120120220111101100202
4103232111220200131133
5134201402312402033
62514401304214115
7166632461304641
oct23562550403537
94716526441322
101355425122143
11482918166864
1219a83516a33b
139aa7bac1cc1
1449862600891
15253cebe88e8
hex13b95a2075f

1355425122143 has 4 divisors (see below), whose sum is σ = 1357903047960. Its totient is φ = 1352947196328.

The previous prime is 1355425122113. The next prime is 1355425122187. The reversal of 1355425122143 is 3412215245531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1355425122143 - 210 = 1355425121119 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1355425122097 and 1355425122106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1355425122113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1238962088 + ... + 1238963181.

It is an arithmetic number, because the mean of its divisors is an integer number (339475761990).

Almost surely, 21355425122143 is an apocalyptic number.

1355425122143 is a deficient number, since it is larger than the sum of its proper divisors (2477925817).

1355425122143 is an equidigital number, since it uses as much as digits as its factorization.

1355425122143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2477925816.

The product of its digits is 144000, while the sum is 38.

The spelling of 1355425122143 in words is "one trillion, three hundred fifty-five billion, four hundred twenty-five million, one hundred twenty-two thousand, one hundred forty-three".

Divisors: 1 547 2477925269 1355425122143