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1355425344331 is a prime number
BaseRepresentation
bin10011101110010101101…
…001010110101101001011
311210120120220220200010221
4103232111221112231023
5134201402342004311
62514401313050511
7166632463221502
oct23562551265513
94716526820127
101355425344331
114829182a8793
1219a835256a37
139aa7bb6c186
144986265b839
15253cec3e671
hex13b95a56b4b

1355425344331 has 2 divisors, whose sum is σ = 1355425344332. Its totient is φ = 1355425344330.

The previous prime is 1355425344283. The next prime is 1355425344337. The reversal of 1355425344331 is 1334435245531.

It is a strong prime.

It is an emirp because it is prime and its reverse (1334435245531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1355425344331 - 29 = 1355425343819 is a prime.

It is a super-2 number, since 2×13554253443312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1355425344337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677712672165 + 677712672166.

It is an arithmetic number, because the mean of its divisors is an integer number (677712672166).

Almost surely, 21355425344331 is an apocalyptic number.

1355425344331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355425344331 is an equidigital number, since it uses as much as digits as its factorization.

1355425344331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1296000, while the sum is 43.

The spelling of 1355425344331 in words is "one trillion, three hundred fifty-five billion, four hundred twenty-five million, three hundred forty-four thousand, three hundred thirty-one".