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135546314053 is a prime number
BaseRepresentation
bin111111000111100110…
…0001001110101000101
3110221212110022012011211
41332033030021311011
54210044324022203
6142134043531421
712535651442113
oct1761714116505
9427773265154
10135546314053
11525373a6a57
122232a229b71
13ca21c82c77
1467bbd3aab3
1537d4c30c6d
hex1f8f309d45

135546314053 has 2 divisors, whose sum is σ = 135546314054. Its totient is φ = 135546314052.

The previous prime is 135546314011. The next prime is 135546314087. The reversal of 135546314053 is 350413645531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99337171684 + 36209142369 = 315178^2 + 190287^2 .

It is a cyclic number.

It is not a de Polignac number, because 135546314053 - 221 = 135544216901 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135546313997 and 135546314015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135546314153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67773157026 + 67773157027.

It is an arithmetic number, because the mean of its divisors is an integer number (67773157027).

Almost surely, 2135546314053 is an apocalyptic number.

It is an amenable number.

135546314053 is a deficient number, since it is larger than the sum of its proper divisors (1).

135546314053 is an equidigital number, since it uses as much as digits as its factorization.

135546314053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324000, while the sum is 40.

Adding to 135546314053 its reverse (350413645531), we get a palindrome (485959959584).

The spelling of 135546314053 in words is "one hundred thirty-five billion, five hundred forty-six million, three hundred fourteen thousand, fifty-three".